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Presidential Elections Statistics > 1996 > Popular Votes for Howard Phillips (most recent) by state

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Showing latest available data.
   New York  24.3%
   Pennsylvania  20.1%
   Virginia  14.1%
   Missouri  11.9%
   Wisconsin  9.1%
   Kansas  3.6%
   Utah  2.7%
   Mississippi  2.4%
   Idaho  2.3%
   Nebraska  2%
   Nevada  1.8%
   Maine  1.6%
   New Hampshire  1.4%
   Rhode Island  1.1%
   Alaska  1%
   South Dakota  0.9%


Rank   States  Amount  (top to bottom)   
#1  New York: 23,580  
#2  Pennsylvania: 19,552  
#3  Virginia: 13,687  
#4  Missouri: 11,521  
#5  Wisconsin: 8,811  
#6  Kansas: 3,519  
#7  Utah: 2,601  
#8  Mississippi: 2,314  
#9  Idaho: 2,230  
#10  Nebraska: 1,928  
#11  Nevada: 1,732  
#12  Maine: 1,517  
#13  New Hampshire: 1,346  
#14  Rhode Island: 1,021  
#15  Alaska: 925  
#16  South Dakota: 912  
Total: 97,196   
Weighted average: 6,074.8   


DEFINITION: Popular votes for Howard Phillips, a candidate from US Taxpayers party (vice-president Herbert Titus), 1996 elections

SOURCE: Dave Leip's Atlas of U.S. Presidential Elections

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