|
SEARCH ALL
|
FACTS & STATISTICS
|
|
Search encyclopedia, statistics and forums:
|
|
|
|
DEFINITION
Popular votes for Roger MacBride, a candidate from Libertarian party (vice-president David Bergland), 1976 elections, percent of total
Presidential Elections Statistics > 1976 > Popular Votes for Roger MacBride (% of total) (most recent) by state
Showing latest available data.
| Rank |
States
|
Amount
(top to bottom)
|
| #1 | Alaska: |
5.49 %
| |
| #2 | Hawaii: |
1.35 %
| |
| #3 | Idaho: |
1.04 %
| |
| #4 | Arizona: |
1.03 %
| |
| #5 | Nevada: |
0.75 %
| |
| #6 | California: |
0.72 %
| |
| #7 | South Dakota: |
0.54 %
| |
| #8 | Colorado: |
0.49 %
| |
| #9 | Utah: |
0.45 %
| |
| #10 | Mississippi: |
0.36 %
| |
| #11 | Kansas: |
0.34 %
| |
| #12 | Washington: |
0.32 %
| |
| #13 | New Jersey: |
0.31 %
| |
| #14 | New Hampshire: |
0.28 %
| |
| #15 | New Mexico: |
0.27 %
| |
| #16 | Virginia: |
0.27 %
| |
| #17 | Louisiana: |
0.26 %
| |
| #18 | Nebraska: |
0.24 %
| |
| |
Weighted average: |
0.8 %
|
|
DEFINITION: Popular votes for Roger MacBride, a candidate from Libertarian party (vice-president David Bergland), 1976 elections, percent of total
See also
Related links:
|