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Presidential Elections Statistics > 1948 > Popular Votes for Harry Truman (% of total) (most recent) by state

VIEW DATA:   Totals  
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Showing latest available data.
Rank   States  Amount  (top to bottom)   
#1  Texas: 65.96 %  
#2  Oklahoma: 62.75 %  
#3  Arkansas: 61.72 %  
#4  Georgia: 60.81 %  
#5  Missouri: 58.11 %  
#6  North Carolina: 58.02 %  
#7  Rhode Island: 57.59 %  
#8  West Virginia: 57.32 %  
#9  Minnesota: 57.16 %  
#10  Kentucky: 56.74 %  
#11  New Mexico: 56.38 %  
#12  Massachusetts: 54.66 %  
#13  Utah: 53.98 %  
#14  Arizona: 53.79 %  
#15  Montana: 53.09 %  
#16  Washington: 52.61 %  
#17  Colorado: 51.88 %  
#18  Wyoming: 51.62 %  
#19  Wisconsin: 50.7 %  
#20  Nevada: 50.37 %  
#21  Iowa: 50.31 %  
#22  Illinois: 50.07 %  
#23  Idaho: 49.98 %  
#24  Ohio: 49.48 %  
#25  Tennessee: 49.14 %  
#26  Florida: 48.82 %  
#27  Indiana: 48.78 %  
#28  Delaware: 48.76 %  
#29  Maryland: 48.01 %  
#30  Connecticut: 47.91 %  
#31  Virginia: 47.89 %  
#32  California: 47.57 %  
#33  Michigan: 47.57 %  
#34  South Dakota: 47.04 %  
#35  Pennsylvania: 46.92 %  
#36  New Hampshire: 46.66 %  
#37  Oregon: 46.4 %  
#38  New Jersey: 45.93 %  
#39  Nebraska: 45.85 %  
#40  New York: 45.01 %  
#41  Kansas: 44.61 %  
#42  North Dakota: 43.41 %  
#43  Maine: 42.27 %  
#44  Vermont: 36.92 %  
#45  Louisiana: 32.75 %  
#46  South Carolina: 24.14 %  
#47  Mississippi: 10.09 %  
Weighted average: 49.3 %   


DEFINITION: Popular votes for Harry Truman, a candidate from Democrat party (vice-president Alben Barkley), 1948 elections, percent of total

SOURCE: Dave Leip's Atlas of U.S. Presidential Elections

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