|
SEARCH ALL
|
FACTS & STATISTICS
|
|
Search encyclopedia, statistics and forums:
|
|
|
|
DEFINITION
Popular votes for Howard Phillips, a candidate from US Taxpayers party (vice-president Herbert Titus), 1996 elections, percent of total
Presidential Elections Statistics > 1996 > Popular Votes for Howard Phillips (% of total) (most recent) by state
Showing latest available data.
| Rank |
States
|
Amount
(top to bottom)
|
| #1 | Virginia: |
0.57 %
| |
| #2 | Missouri: |
0.53 %
| |
| #3 | Idaho: |
0.45 %
| |
| #4 | Pennsylvania: |
0.43 %
| |
| #5 | Wisconsin: |
0.4 %
| |
| #6 | Utah: |
0.39 %
| |
| #7 | Alaska: |
0.38 %
| |
| #8 | Nevada: |
0.37 %
| |
| #9 | New York: |
0.37 %
| |
| #10 | Kansas: |
0.33 %
| |
| #11 | South Dakota: |
0.28 %
| |
| #12 | Nebraska: |
0.28 %
| |
| #13 | New Hampshire: |
0.27 %
| |
| #14 | Mississippi: |
0.26 %
| |
| #15 | Rhode Island: |
0.26 %
| |
| #16 | Maine: |
0.25 %
| |
| |
Weighted average: |
0.4 %
|
|
DEFINITION: Popular votes for Howard Phillips, a candidate from US Taxpayers party (vice-president Herbert Titus), 1996 elections, percent of total
See also
Related links:
|
del.icio.us
Feeds |
Contact