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Presidential Elections Statistics > 1996 > Popular Votes for Harry Browne (% of total) (most recent) by state

VIEW DATA:   Totals  
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Showing latest available data.
Rank   States  Amount  (top to bottom)   
#1   Arizona: 1.02 %  
#2   Nevada: 0.96 %  
#3   Alaska: 0.94 %  
#4   New Hampshire: 0.85 %  
#5   Wyoming: 0.82 %  
#6   Colorado: 0.82 %  
#7   Massachusetts: 0.8 %  
#8   Georgia: 0.78 %  
#9   Delaware: 0.76 %  
#10   California: 0.73 %  
#11   Indiana: 0.73 %  
#12   Michigan: 0.72 %  
#13   Hawaii: 0.69 %  
#14   Idaho: 0.68 %  
#15   Oregon: 0.65 %  
#16   Montana: 0.62 %  
#17   Pennsylvania: 0.62 %  
#18   Utah: 0.62 %  
#19   Washington: 0.56 %  
#20   New Mexico: 0.54 %  
#21   Illinois: 0.52 %  
#22   Missouri: 0.49 %  
#23   Maryland: 0.49 %  
#24   Maine: 0.49 %  
#25   New Jersey: 0.48 %  
#26   West Virginia: 0.48 %  
#27   Oklahoma: 0.46 %  
#28   Vermont: 0.46 %  
#29   South Dakota: 0.45 %  
#30   Florida: 0.45 %  
#31   Connecticut: 0.42 %  
#32   Kansas: 0.42 %  
#33   Louisiana: 0.42 %  
#34   Nebraska: 0.41 %  
#35   Minnesota: 0.38 %  
#36   Virginia: 0.38 %  
#37   South Carolina: 0.37 %  
#38   Wisconsin: 0.36 %  
#39   Texas: 0.36 %  
#40   Arkansas: 0.35 %  
#41   North Carolina: 0.35 %  
#42   Alabama: 0.34 %  
#43   North Dakota: 0.32 %  
#44   District of Columbia: 0.32 %  
#45   Mississippi: 0.31 %  
#46   Kentucky: 0.29 %  
#47   Rhode Island: 0.28 %  
#48   Ohio: 0.28 %  
#49   Tennessee: 0.27 %  
Weighted average: 0.5 %   


DEFINITION: Popular votes for Harry Browne, a candidate from Libertarian party (vice-president Jo Jorgensen), 1996 elections, percent of total

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