Normally, to check that f is a homeomorphism, one would have to verify that both f and its inverse functionf -1 are continuous; the theorem says that if the domain is an open subset of Rn and the image is also in Rn, then continuity of f -1 is automatic. Furthermore, the theorem says that if two subsets U and V of Rn are homeomorphic, and U is open, then V must be open as well. Both of these statements are not at all obvious and are not generally true if one leaves Euclidean space.
An important consequence of the domain invariance theorem is that Rn cannot be homeomorphic to Rm if m ≠ n. Indeed, no non-empty open subset of Rn can be homeomorphic to any open subset of Rm in this case. (If n < m, then we can view Rn as a subspace of Rm, and the non-empty open subsets of Rn are not open as subsets of Rm.)
The domain invariance theorem may be generalized to manifolds: if M and N are topological n-manifolds without boundary and f : M → N is a continuous map which is locally one-to-one (meaning that every point in M has a neighborhood such that f restricted to this neighborhood is injective), then f is an open map (meaning that f(U) is open in M whenever U is an open subset of M).
Share your thoughts, questions and commentary here
Want to know more? Search encyclopedia, statistics and forums:
Press Releases |
The Wikipedia article included on this page is licensed under the
Images may be subject to relevant owners' copyright.
All other elements are (c) copyright NationMaster.com 2003-5. All Rights Reserved.
Usage implies agreement with terms, 1022, m